2/3x+5=x^2-x+3

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Solution for 2/3x+5=x^2-x+3 equation: 



2/3x+5=x^2-x+3

We move all terms to the left:

2/3x+5-(x^2-x+3)=0



Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R



We get rid of parentheses

-x^2+2/3x+x-3+5=0

We multiply all the terms by the denominator


-x^2*3x+x*3x-3*3x+5*3x+2=0

Wy multiply elements

-3x^3+3x^2-9x+15x+2=0

We do not support expression: x^3

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